An electrono of mass m, when accelerated through a potential difference V, has de-Broglie wavelength `lambda`. The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference, will be:

Options

A. `lambda(M)/(m)`
B. `lambda(m)/(M)`
C. `lambdasqrt(M/m)`
D. `lambdasqrt(m/M)`