A particle of mass 10 g is describing SHM along a straight line with a period of 2 s and amplitude of 10 cm. what is the kinetic energy when it is (i) 2 cm (ii) 5 cm, from its equilibrium positio ? How do you account for the difference between its two values.?

A particle of mass 10g is describing SHM along a straight line with a period of 4s and amplitude 12 cm. What is the kinetic energy when it is (i) 3cm (ii) 6 cm from its equilibrium position. How do you account for the difference between the two values ? [use pi^(2)=10]

A particle of mass 100g is dexcribing SHM along a straight lig with a period of 2s and amplitude of 12 cm. What is the knetice energy when it is (i) 3cm (ii) 6cm from its equilibrium position? (Use pi^(2)=10)

A particle of mass 10 gm is describing S.H.M. along a straight line with period of 2 sec and amplitude of 10 cm . Its kinetic energy when it is at 5 cm from its equilibrium position is

A particle describes SHM along a straight line with a period of 2 s and amplitude 10 cm. Its velocity when it is at a distance of 6 cm from mean position is

A particale in S.H.M. has a perod of 2 seconds and amplitude of 10 cm. Calculate the acceleration when it is at 4 cm from its positive extreme position.

A particle of mass 10g is undergoing SHM of amplitude 10cm and period 0.1s. The maximum value of force on particle is about

A tiny mass performs S.H.M along a straight line with a time period of T=0.60sec and amplitude A=10.0cm. Calculate the mean velocity (in m/sec) in the time to displace by A/2 .

A point performs SHM along a straight line with a period T = 0.60 s and amplitude a = 10 cm. Starting from extreme position, in what time, the point travels a distance a/2 ?

A particle executes SHM along a straight line so that its period is 12 s. The time it takes in traversing a distance equal to half its amplitude from its equilibrium position is

A particle exectes S.H.M. along a straight line with mean position x = 0 , period 20 s amplitude 5 cm . The shortest time taken by the particle to go form x = 4 cm to x = -3 cm is