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A particle is projected at an angle of t...

A particle is projected at an angle of `theta` with the horizontal, with initial speed `u`.If the magnitude of velocity of projectile motion and time are related as `v^(2)-100t^(2)+400t-800=0`. Then which of the following is/are correct. (Take `g=10m//s^(2)`)

A

Angle of projection is `45^(@)`

B

Maximum height attained by the particle is `20` meter

C

Range of the particle is 80 meter

D

Projection velocity is 40 m/sec

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
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Knowledge Check

  • A particle is pojected from the ground at an angle of theta with the horizontal with an initial speed of u . Time after which velocity vector of the projectile is perpendicular to the initial velocity is

    A
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    B
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    C
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    D
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    A
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    B
    If `u=10sqrt(3)m//s and theta=60^(@)`, then time of flight will be 3 sec.
    C
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    D
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