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A particle performs SHM of amplitude A a...

A particle performs `SHM` of amplitude `A` along a straight line .When it is at a distance of `sqrt(3)/(2)`A from mean position its kinetic energy gets increased by an amount of `(1)/(2) m omega^(2)A^(2)` due to an impulsive force. Then its new amplitude becomes

A

`sqrt(5)/2`A

B

`sqrt(3)/2`A

C

`sqrt(2)`A

D

`2/sqrt(5)`A

Text Solution

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The correct Answer is:
C
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