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Two particles undergo SHM along the same...

Two particles undergo `SHM` along the same line with the same time period `(T)` and equal amplitude `(A)`. At a particular instant one is at `x =- A` and the other is at `x =0`. If they start moving in the same direction then they will cross each other at

(i) `t = (4T)/(3)` (ii) `t = (3T)/(8)` (iii) `x = (A)/(2)` (iv) `x = (A)/(sqrt(2))`

A

`t=(4T)/3

B

`t=(3T)/8`

C

`x=A/2`

D

`x=(A/sqrt(2))`

Text Solution

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The correct Answer is:
B, D
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