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Two particles are in SHM with same ampli...

Two particles are in SHM with same amplitude A and same regualr frequency `omega`. At time t=0, one is at x =`+A/2` and the other is at `x=-A/2`. Both are moving in the same direction.

A

phase difference between the two particles is `pi/3`

B

phase difference between the two particles is `(2pi)/3`

C

they will collide after time t= `pi/(2omega)`

D

they will collide after time t=`(3pi)/(4omega)`

Text Solution

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The correct Answer is:
A, C
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