A ray of light suffers minimum deviation, while passing through a prism of refractive index `1.5` and refracting angle `60^@`. Calculate the angle of deviation and angle in incidence.

A ray of light suffers minimum deviation while passing through a prism of refracting angle A . If the angle of incidence i = Refractive angle and n = sqrt3 , find the angle of the prism .

A ray of monochromatic light suffers minimum deviation of 38^(@) while passing through a prism of refracting angle 60^(@) . Refracting index of the prism material is

A ray of light suffers a minimum deviation when incident on equilateral prism of refractive index sqrt2 The angle of deviation is

A ray of light suffers minimum deviation when incident on an equilateral prism of refractive index sqrt2 . What is the angle of incidence ?

A ray of light suffers a minimum deviation when incident on an equilateral prism of refractive index sqrt(2) The angle of incidence is

A ray of light suffers minimum deviation through a prism of refractive index sqrt(2) . What is the angle of prism if the angle of incidence is double the angle of refraction within the prism?

A prism of refractive index sqrt(2) has refractive angle 60^(@) . Find the angle of incidence so that a ray minimum deviation.

A prism of refractive index sqrt2 has refractive angle 60^@. In the order that a ray suffers minimum deviation it should be incident at an angle of

The angle of minimum deviation of a prism of refractive index sqrt(3) is equal to its refracting angle. Then the refracting angle of that prism is

The angle of minimum deviation of a prism of refractive index sqrt(3) is equal to its refracting angle. Then the refracting angle of the prism is