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underset(("bot"))(Cu+conc.HNO(3))toCu(NO...

`underset(("bot"))(Cu+conc.HNO_(3))toCu(NO_(3))_(2)+X`
(oxide of nitrogen) then X is:

A

`N_(2)O`

B

`NO_(2)`

C

`NO`

D

`N_(2)O_(3)`

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The correct Answer is:
B
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