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Statement-1: Many copper (I) compound ar...

Statement-1: Many copper (I) compound are unstable in aqueous solution and undergo disproportionation.
Statement-2: `Cu^(2+)` I mre stable than `Cu^(+)` because of much more negative `Delta_(hyd)H^(@)` of `Cu^(2+)` than `Cu^(+)`, which more than compensates for seconds ionisation enthalpy.

A

Statement-1 is true, statement-2 is true, statement-2 is a correct explanation for statement-1.

B

Statement-1 is true, statement-2 is true, statement-2 is NOT a correct explanation for statement-1

C

Statement-1 is true, statement-2 is false.

D

statement-1 is false, statement-2 is true.

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • The unique behaviour of CU, having a positive E^(@) (reduction potential) accounts for its inability to liberate H_(2) from acids,. Only oxidising acids (nitric acid and hot concentrated sulphuric acid) react with Cu. The high energy of transform Cu(s) to Cu^(2+)(aq.) is not balanced by its hydration enthalpy. On the other hand, All Cu(II) halides are known except iodide. in this case, Cu^(2+) oxidises I^(-) to I_(2) : 2Cu^(2+)+4I^(-) to 2CuI(s)+I_(2) However, copper (I) compounds are unstable in aqueous solution annd undergo disproportionation. 2Cu^(+)(aq.)toCu^(2+)(aq.)+Cu The stability of Cu^(2+)(aq.) rather than Cu^(+)(aq) is due to the much more negative Delta_(Hyd) of Cu^(2+)(aq.) than Cu^(+)(aq.) Q. Select the correct chemical change:

    A
    `Cu+Dil.H_(2)SO_(4) to CuSO_(4)+H_(2)(g)`
    B
    `Cu+dil.HNO_(3) to Cu(NO_(3))_(2)+N_(2)O(g)`
    C
    `CuSO_(4)(aq.)+KCN(excess)toK_(2)[Cu(CN)_(4)]`
    D
    `CuSO_(4)(aq.)+NH_(4)OH to Cu(OH)_(2)darr`

  • The unique behaviour of CU, having a positive E^(@) (reduction potential) accounts for its inability to liberate H_(2) from acids,. Only oxidising acids (nitric acid and hot concentrated sulphuric acid) react with Cu. The high energy of transform Cu(s) to Cu^(2+)(aq.) is not balanced by its hydration enthalpy. On the other hand, All Cu(II) halides are known except iodide. in this case, Cu^(2+) oxidises I^(-) to I_(2) : 2Cu^(2+)+4I^(-) to 2CuI(s)+I_(2) However, copper (I) compounds are unstable in aqueous solution annd undergo disproportionation. 2Cu^(+)(aq.)toCu^(2+)(aq.)+Cu The stability of Cu^(2+)(aq.) rather than Cu^(+)(aq) is due to the much more negative Delta_(Hyd) of Cu^(2+)(aq.) than Cu^(+)(aq.) Q. Select the correct chemical change:

    A
    `Cu+Dil.H_(2)SO_(4) to CuSO_(4)+H_(2)(g)`
    B
    `Cu+dil.HNO_(3) to Cu(NO_(3))_(2)+N_(2)O(g)`
    C
    `CuSO_(4)(aq.)+KCN(excess)toK_(2)[Cu(CN)_(4)]`
    D
    `CuSO_(4)(aq.)+NH_(4)OH to Cu(OH)_(2)darr`

  • The unique behaviour of CU, having a positive E^(@) (reduction potential) accounts for its inability to liberate H_(2) from acids,. Only oxidising acids (nitric acid and hot concentrated sulphuric acid) react with Cu. The high energy of transform Cu(s) to Cu^(2+)(aq.) is not balanced by its hydration enthalpy. On the other hand, All Cu(II) halides are known except iodide. in this case, Cu^(2+) oxidises I^(-) to I_(2) : 2Cu^(2+)+4I^(-) to 2CuI(s)+I_(2) However, copper (I) compounds are unstable in aqueous solution annd undergo disproportionation. 2Cu^(+)(aq.)toCu^(2+)(aq.)+Cu The stability of Cu^(2+)(aq.) rather than Cu^(+)(aq) is due to the much more negative Delta_(Hyd) of Cu^(2+)(aq.) than Cu^(+)(aq.) Q. Consider the following transformation: CuSO_(4)(aq.)+KI(excess)to product Select the correct statement:

    A
    Product contains `[Cu(H_(2)O_(4))]^(2+)` ion.
    B
    Presence of brown colouration in product is due to `I_(3)^(-)` ion
    C
    Oxidation state of sulphur in reactant and product is different
    D
    white ppt. of `CuI_(2)` is observed in product

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