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Evaluate the definite integrals int1 ^2...

Evaluate the definite integrals
`int_1 ^2(5x^2)/(x^2+4x+3)`

Text Solution

Verified by Experts

Solution :
Let I = `int _2^1(((6x^2)/x^+4x+3))dx`
=>`I=[I1]_2^1`
Therefore, `I1=int (5x^2)/ (x^2+4x+3)dx=>I1= int 5+(-20x-15)/(x^2+4x+3)dx`
=`int 5dx-5 int(4x+3)/((x+3)(x+1))dx`
=`int 5x-5 int(4x+3)/((x+3)(x+1))dx`
`(4x+3)/((x+3)(x+1))=A/(x+3)+B/(x+1) ...
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