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Least count of a vernier callipers is 0....

Least count of a vernier callipers is `0.01 cm` When the two jaws of the instrument touch each other the `5th` division of the vernier scale coincide with a main scale division and the zero of the vernier scale lies to the left of the zero of the main scale. Furthermore while measuring the diameter of a sphere, the zero markof the vernier scale lies between `2.4 cm` and `2.5 cm` and the `6th` vernier division coincides with a main scale division. Calculate the diameter of the sphere.

Text Solution

Verified by Experts

The instrument has a negative error,
`e=(-5xx0.01)cm`
or `e=-0.05 cm`
Measured reading `=(2.4+6xx0.01)=2.46 cm`
True reading = Measured reading `- e`
`=2.46-(-0.05)`
`=2.51 cm`
Therefore, diameter of the sphere is `2.51` cm.
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