Home
Class 12
PHYSICS
Calculate the distance from the surface ...

Calculate the distance from the surface of the earth at which above the surface, acceleration due to gravity is the same.

Text Solution

Verified by Experts

`h = (sqrt(5) - 1)/(2)R`
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    MOTION|Exercise Exercise - 3 | Level - II (Subjective | JEE Advanced)|10 Videos
  • GRAVITATION

    MOTION|Exercise Exercise - 4 | Level - I (Previous year | JEE Main)|16 Videos
  • GRAVITATION

    MOTION|Exercise Exercise - 2 (Level - II) Multiple choice | JEE Advanced|12 Videos
  • GEOMETRICAL OPTICS

    MOTION|Exercise Exercise - 4 | Level-II|55 Videos
  • HEAT - 1

    MOTION|Exercise EXERCISE -4 (Level - II) Previous Year | JEE Advanced|22 Videos

Similar Questions

Explore conceptually related problems

An object is projected vertically upward from the surface of the earth at which above and below the surface acceleration due to gravity is the same.

" The distance from the surface of the earth at which the acceleration due to gravity is the same below and above the surface of the earth."

Let g be the acceleration due to gravity on the earth's surface.

Calculate the depth below the surface of the earth where acceleration due to gravity becomes half of its value at the surface of the earth . Radius of the earth = 6400 km.

At a height equal to earth's radius, above the earth's surface, the acceleration due to gravity is

The acceleration of a body due to the attraction of the earth (radius R) at a distance 2R form the surface of the earth is (g=acceleration due to gravity at the surface of the earth)

A body is projected vertically upward from the surface of the earth with escape velocity. Calculate the time in which it will be at a height (measured from the surface of the arth) 8 time the radius of the earth (R). Acceleration due to gravity on the surface of the earth is g.

The satellite is moving round the earth (radius of earth = R) at a distance r from the centre of the earth. If g is the acceleration due to gravity on the surface of the earth. The acceleration of the satellite will be

A body is taken to a height of nR from the surface of the earth . The ratio of acceleration due to gravity on the surface to that at the altitude is

At what distance from the centre of the earth, the value of acceleration due to gravity g will be half that on the surface ( R = radius of earth)