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Integrate the function (x^2+1)logx...

Integrate the function `(x^2+1)logx`

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To solve the integral \(\int (x^2 + 1) \log x \, dx\), we can break it down into two parts: \[ \int (x^2 + 1) \log x \, dx = \int x^2 \log x \, dx + \int \log x \, dx \] ### Step 1: Integrate \(x^2 \log x\) ...
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