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The boiling point of benzene is 80.1^(@)...

The boiling point of benzene is `80.1^(@)C`. At ordinary pressure and `70^(@)C`, the benzene vapour spontaneously transforms into liquid benzene. In this process, what will the signs of `DeltaH,DeltaS and Delta G` be?

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The entropy of the system decreases when a vapour transforms into a liquid so `DeltaS lt0`. Gain, the condensation is an exothermic process. So, in this process, `DeltaH lt 0`. Under the given conditions, the benzene vapour spontaneously condenses into liquid. so, in this process `DeltaG lt0`.
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CHHAYA PUBLICATION-CHEMICAL THERMODYNAMICS-QUESTION ANSWER ZONE FOR BOARD EXAMINATION (SHORT ANSWER TYPE)
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