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In S(N)2 reactions, the correct order of...

In `S_(N)2` reactions, the correct order of reacitivity for the following compounds:
`CH_(3)Cl, CH_(3)CH_(2)Cl, (CH_3)_(2)CHCl` and `(CH_3)_(3)C Cl` is-

A

`(CH_3)_(2)CHCl gt CH_(3)CH_(2)Cl gt CH_(3)Cl gt (CH_3)_(3)C Cl`

B

`CH_(3)Cl gt (CH_3)_(2)CHCl gt CH_(3)CH_(2)Cl gt(CH_3)_(3)C Cl`

C

`CH_(3)Cl gtCH_(3)CH_(2)Cl gt (CH_3)_(2)CHCl gt (CH_3)_(3)C Cl`

D

`CH_(3)CH_(2)Cl gt CH_(3)Cl gt (CH_3)_(2)CHCl gt(CH_3)_(2)C Cl`

Text Solution

Verified by Experts

The correct Answer is:
C
Steric hindrance gets increased by increase in the number of alkyl groups on `alpha`-carbon. As a result, attack of nucleophile from backside to `alpha`-carbon in `S_(N)2` reaction gets hanpered. Thus, the order of increasing `S_(N)2` reactivity is-
`CH_(3)Cl > CH_(3)CH_2)Cl > (CH_(3))_(2)CHCl > (CH_3)_(3)C Cl`.
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