2,2-dichloropropane on hydrolysis yields -

Options

A. Acetone
B. 2,2-Propane diol
C. Isopropyl alcohol
D. Acetaldehyde

Answer

To solve the question of what 2,2-dichloropropane yields upon hydrolysis, we can follow these steps:

### Step 1: Identify the structure of 2,2-dichloropropane
2,2-Dichloropropane has the following structure:
- It consists of a propane backbone (3 carbon atoms).
- The second carbon has two chlorine atoms attached to it.

The structure can be represented as:
```
Cl
|
CH3- C - CH3
|
Cl
```

### Step 2: Understand the hydrolysis process
Hydrolysis involves the reaction of a compound with water. In this case, we will consider hydrolysis in a basic medium using aqueous KOH. The hydroxide ions (OH⁻) will replace the chlorine atoms.

### Step 3: Perform hydrolysis
When 2,2-dichloropropane undergoes hydrolysis:
- The two chlorine atoms (Cl) on the second carbon will be replaced by hydroxyl groups (OH).
- The reaction can be represented as follows:
```
OH
|
CH3- C - CH3
|
OH
```

### Step 4: Analyze the stability of the product
The product formed is 2,2-propanediol (with two OH groups on the second carbon). However, having two hydroxyl groups on the same carbon is unstable. Therefore, to achieve stability, a water molecule (H₂O) must be eliminated.

### Step 5: Eliminate water to form a double bond
By removing a water molecule from the product, we can form a double bond between the second carbon and the oxygen:
- The reaction can be represented as:
```
O
||
CH3- C - CH3
```
This structure corresponds to acetone (also known as propan-2-one).

### Final Answer
Thus, the final product of the hydrolysis of 2,2-dichloropropane is **acetone**.

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