Ozonolysis of 2-methylbut-2-ene yields -

Options

A. Only aldehyde
B. Only ketone
C. Both aldehyde and ketone
D. None

Answer

To solve the question regarding the ozonolysis of 2-methylbut-2-ene, we will follow these steps:

### Step 1: Draw the Structure of 2-Methylbut-2-ene
2-methylbut-2-ene is an alkene with the following structure:
- It has a total of 5 carbon atoms.
- The double bond is located between the second and third carbon atoms.
- There is a methyl group attached to the second carbon.

The structure can be represented as:
```
CH3
|
CH3 - C = C - CH2 - CH3
```

### Step 2: Understand the Ozonolysis Reaction
Ozonolysis is a reaction where ozone (O3) reacts with alkenes to form carbonyl compounds (aldehydes or ketones). The alkene will undergo cleavage at the double bond.

### Step 3: Ozone Addition
When ozone is added to 2-methylbut-2-ene, it forms a molozonide intermediate. The double bond of the alkene attacks the ozone molecule, resulting in the formation of a cyclic ozonide.

### Step 4: Rearrangement and Cleavage
The molozonide is unstable and rearranges to form a more stable ozonide. The ozonide then undergoes cleavage, breaking the bonds and forming carbonyl compounds.

### Step 5: Identify the Products
For 2-methylbut-2-ene, the ozonolysis will yield:
- One molecule of acetone (a ketone)
- One molecule of acetaldehyde (an aldehyde)

The final products can be summarized as:
- Acetone (CH3COCH3)
- Acetaldehyde (CH3CHO)

### Final Answer
Ozonolysis of 2-methylbut-2-ene yields acetone and acetaldehyde.

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