Which set of products is expected on reductive ozonolysis of the following diolefin ?
`CH_(3)CH=overset(CH_(3))overset(|)(C)-CH=CH_(2)`

Options

A. `CH_(3)CHO,CH_(3)COCH = CH_(2)`
B. `CH_(3)CH = C(CH_(3))CHO, CH_(2)O`
C. `CH_(3)CHO, CH_(3)COCHO, CH_(2)O`
D. `CH_(3)CHO,CH_(3)COCH_(3), CH_(2)O`

Answer

To determine the products of the reductive ozonolysis of the diolefin given as `CH3CH=CH(CH3)CH=CH2`, we will follow these steps:

### Step 1: Identify the structure of the diolefin
The given diolefin can be represented as follows:
- The structure is:
```
CH3
|
CH3-CH=CH-CH=CH2
```
This shows that there are two double bonds present in the molecule.

### Step 2: Understand the mechanism of ozonolysis
In ozonolysis, the alkene undergoes a reaction with ozone (O3) leading to the formation of an ozonide intermediate. This is a 1,3-cycloaddition reaction where ozone adds across the double bonds.

### Step 3: Draw the ozonide intermediate
When the diolefin reacts with ozone, it forms an ozonide. The ozonide can be represented as:
```
O
/ \
O O
```
This ozonide will then undergo cleavage.

### Step 4: Perform the retro-aldol reaction
The ozonide will break down (retro-aldol reaction) to yield carbonyl compounds. In this case, the double bonds will break, and we will form two carbonyl compounds (aldehydes or ketones).

### Step 5: Determine the products
For the diolefin `CH3CH=CH(CH3)CH=CH2`, the cleavage will occur at the double bonds, leading to the formation of the following products:
1. Acetone (from the cleavage of the first double bond)
2. Propanal (from the cleavage of the second double bond)

Thus, the expected products from the reductive ozonolysis of the diolefin are:
- Acetone (CH3COCH3)
- Propanal (CH3CHO)

### Final Answer:
The set of products expected from the reductive ozonolysis of the diolefin `CH3CH=CH(CH3)CH=CH2` is Acetone and Propanal.

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