`CHCl_(3) + CH_(3)C Cl_(3) + 6Ag rarr A + 6AgCl`. The compound A is -

Options

A. `CH-=CH`
B. `CH_(3)-C-=CH`
C. `CH_(3)-CH=CH_(2)`
D. `CH_(2)=CH_(2)`

Answer

To solve the question, we need to analyze the reaction given:

**Reaction:**
\[ \text{CHCl}_3 + \text{CH}_3\text{CCl}_3 + 6\text{Ag} \rightarrow A + 6\text{AgCl} \]

### Step-by-Step Solution:

1. **Identify the Reactants:**
- The reactants are chloroform (CHCl3) and 1,1,1-trichloroethane (CH3CCl3).
- Chloroform is a simple alkane with three chlorine atoms attached to a carbon, while 1,1,1-trichloroethane has three chlorine atoms attached to a carbon that is also connected to a methyl group.

2. **Understand the Role of Silver (Ag):**
- Silver (Ag) acts as a reducing agent in this reaction. It will help in the removal of chlorine atoms from the organic compounds, leading to the formation of a new compound (A) and silver chloride (AgCl) as a byproduct.

3. **Analyze the Reaction:**
- The reaction indicates that both chloroform and 1,1,1-trichloroethane will lose chlorine atoms.
- Each molecule of chloroform (CHCl3) can lose one chlorine atom, and each molecule of 1,1,1-trichloroethane (CH3CCl3) can also lose one chlorine atom.

4. **Determine the Product (A):**
- After the reaction, we will have a compound that has fewer chlorine atoms.
- The likely product (A) formed from the reaction of chloroform and 1,1,1-trichloroethane in the presence of silver would be a hydrocarbon with reduced chlorine content.
- The most probable product (A) is a hydrocarbon, specifically ethane (C2H6), since both reactants lose their chlorine atoms.

5. **Write the Final Equation:**
- The final equation can be summarized as:
\[ \text{CHCl}_3 + \text{CH}_3\text{CCl}_3 + 6\text{Ag} \rightarrow \text{C}_2\text{H}_6 + 6\text{AgCl} \]

### Conclusion:
The compound A is **ethane (C2H6)**.