1-Butyne is formed when ethyl bromide is heated with -

Options

A. Sodium ethoxide
B. Silver acrylate
C. Sodium acetylide
D. Silver acetate

Answer

To determine how 1-butyne is formed from ethyl bromide, we can follow these steps:

### Step 1: Identify the Reactants
1-Butyne has the structure CH≡C-CH2-CH3, and ethyl bromide is CH3CH2Br.

### Step 2: Understand the Role of Sodium Acetylide
Sodium acetylide (NaC≡CH) is a strong nucleophile. It is formed from acetylene (HC≡CH) by reacting it with sodium amide (NaNH2). Sodium acetylide will be used to react with ethyl bromide.

### Step 3: Nucleophilic Substitution Reaction
In the reaction, the nucleophilic carbon from sodium acetylide (C≡C-) will attack the electrophilic carbon in ethyl bromide (CH3CH2Br). The bromine atom acts as a leaving group.

### Step 4: Reaction Mechanism
1. The nucleophile (C≡C-) attacks the ethyl bromide (CH3CH2Br), resulting in the formation of 1-butyne (CH≡C-CH2-CH3) and sodium bromide (NaBr).
2. The reaction can be summarized as:
\[ \text{NaC≡CH} + \text{CH3CH2Br} \rightarrow \text{CH≡C-CH2-CH3} + \text{NaBr} \]

### Step 5: Conclusion
The product formed from the reaction of sodium acetylide with ethyl bromide is 1-butyne.

### Final Answer
1-Butyne is formed when ethyl bromide is heated with sodium acetylide.

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