Hydration of propyne gives -

Options

A. 1-Propanol
B. 2-Propanol
C. Propanal
D. Propanone

Answer

To determine the product of the hydration of propyne, we can follow these steps:

### Step 1: Understand Hydration
Hydration is the addition of water (H₂O) to an alkene or alkyne in the presence of an acid catalyst, typically sulfuric acid (H₂SO₄). In this case, we are hydrating propyne (C₃H₄).

### Step 2: Write the Reaction
The reaction can be represented as:
\[ \text{C₃H₄} + \text{H₂O} \xrightarrow{\text{H₂SO₄}} \text{Product} \]

### Step 3: Identify the Structure of Propyne
Propyne has the structure:
\[ \text{CH₃C≡CH} \]
This means it has a triple bond between the second and third carbon atoms.

### Step 4: Protonation of the Alkyne
In the presence of sulfuric acid, the triple bond will be protonated. The proton (H⁺) will add to one of the carbon atoms involved in the triple bond, forming a more stable carbocation. The more stable carbocation will be a secondary carbocation.

### Step 5: Formation of the Carbocation
When the proton adds to the terminal carbon (C1), we get:
\[ \text{CH₃C}^+ \text{H-CH₂} \]
This is a secondary carbocation.

### Step 6: Nucleophilic Attack by Water
Water (H₂O) will then attack the carbocation, leading to the formation of an alcohol. The oxygen from water will bond with the carbocation, and we will have:
\[ \text{CH₃C(OH)-CH₂} \]

### Step 7: Deprotonation
The oxygen will have a positive charge after the attack, so it will lose a proton (H⁺) to form the alcohol:
\[ \text{CH₃C(OH)-CH₂} \]

### Step 8: Final Product
The final product after hydration of propyne is:
\[ \text{CH₃C(OH)-CH₂} \]
This compound is known as **2-propanol** or **isopropyl alcohol**.

### Summary of the Reaction
The hydration of propyne results in the formation of 2-propanol.

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