Westrosol is a solvent & it is prepared by -

Options

A. `CH-=CH+2Cl_(2)`
B. `CH-=CH+2HCl&` then `Ca(OH)_(2)`
C. `CH-=CH+2Cl_(2)&Ca(OH)_(2)`
D. none of these

Answer

To prepare Westrosol, we need to follow a series of chemical reactions starting from acetylene (ethyne). Here’s a step-by-step breakdown of the preparation process:

### Step 1: Starting Material
- **Identify the starting material**: We begin with acetylene (C₂H₂), which is a simple alkyne with a triple bond between the two carbon atoms.

### Step 2: Chlorination of Acetylene
- **Add chlorine**: We react acetylene with chlorine (Cl₂) in the presence of carbon tetrachloride (CCl₄) as a solvent. This reaction introduces chlorine atoms into the molecule.

**Reaction**:
\[ C_2H_2 + Cl_2 \xrightarrow{CCl_4} 1,2-Dichloroethene (C_2H_2Cl_2) \]

### Step 3: Further Chlorination
- **Chlorinate again**: The product from Step 2 (1,2-dichloroethene) is then subjected to further chlorination. We add another molecule of chlorine to this compound.

**Reaction**:
\[ C_2H_2Cl_2 + Cl_2 \rightarrow 1,1,2,2-Tetrachloroethane (C_2H_2Cl_4) \]

### Step 4: Dehydrochlorination
- **Remove HCl**: To convert tetrachloroethane to Westrosol, we need to remove one of the chlorine atoms. This is done by treating the compound with a base, such as calcium hydroxide (Ca(OH)₂), which acts to deprotonate the compound and eliminate HCl.

**Reaction**:
\[ C_2H_2Cl_4 + Ca(OH)_2 \rightarrow C_2HCl_3 + HCl \]

### Step 5: Final Product
- **Formation of Westrosol**: The final product after the elimination of HCl is Westrosol, which is identified as 1,1,2-trichloroethene (C₂HCl₃).

### Summary of the Preparation
1. Start with acetylene (C₂H₂).
2. Chlorinate to form 1,2-dichloroethene (C₂H₂Cl₂).
3. Chlorinate again to form 1,1,2,2-tetrachloroethane (C₂H₂Cl₄).
4. Treat with calcium hydroxide to remove HCl and form Westrosol (C₂HCl₃).