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CH(2)= CHCH(2)CH=CH(2) overset(NBS)rarr ...

` CH_(2)= CHCH_(2)CH=CH_(2) overset(NBS)rarr X(` Major `),(X)` is `:`

A

`CH_(2)=CHunderset(Br)underset(|)(CH)CH=CH_(2)`

B

`CH_(2)=CHCH=CH-CH_(2)Br`

C

`CH_(2)=CHCH_(2)CH=CHBr`

D

`CH_(2)=underset(Br)underset(|)(CHCH_(2))C=CH_(2)`

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The correct Answer is:
A, B
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