The velocity of an object is changing with time and relation is given by the following equation.
`v=2t+3t^(2)`
Calculate the position of the object from the origin at `t=2s.`

Explanation

To find the position of the object from the origin at \( t = 2 \, \text{s} \) given the velocity function \( v(t) = 2t + 3t^2 \), we need to integrate the velocity function with respect to time. Here are the steps to solve the problem:

### Step 1: Write the relationship between velocity and position
The velocity \( v \) is defined as the rate of change of position \( s \) with respect to time \( t \):
\[ v = \frac{ds}{dt} \]
Given the velocity function:
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