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Three six-faced dice are thrown together...

Three six-faced dice are thrown together. The probability that the sum of the numbers appearing on the dice is `k(3 le k le 8)`, is

A

`((k-1)(k-2))/(432)`

B

`(k(k-2))/(432)`

C

`.^(k-1)C_(2)xx(1)/(215)`

D

`(k^2)/(432)`.

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