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A steady current i flows in a small squa...

A steady current `i` flows in a small square lopp of wire of side `L` in a horizontal plane. The loop is now folded about its middle such that half of it lies in a vertical plane. Let `vecmu_(1)` and `vecmu_(2)` respectively denote the magnetic moments due to the current loop before and after folding. Then

A

`vecmu_(2)=0`

B

`vecmu_(1)` and `vecmu_(2)`are in the same direction

C

`|vecmu_(1)|/|vecmu_(2)|=sqrt2`

D

`|vecmu_(1)|/|vecmu_(2)|=1/sqrt2`

Text Solution

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The correct Answer is:
C
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RESONANCE-ELECTRODYNAMICS-Exercise-1 PART-2
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