A bar magnet has a magnetic moment 2.5JT...

A bar magnet has a magnetic moment `2.5JT^(-1)` and is placed in a magnetic field of `0.2 T`. Calculate the work done in turning the magnet from parallel to antiparallel position relative to field direction.

`0.5 J`

`1 J`

`2.0 J`

zero

Text Solution

Verified by Experts

The correct Answer is:

`U_(i)=-MB`
`U_(f)=MB`
`W=DeltaU=2 MB=2xx2.5xx0.2 =1J`

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