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The sum of 'n' terms of an A.P is 715.If...

The sum of 'n' terms of an A.P is 715.If first term is incrased by 1, second term is increased by 3, third term is increased by 5 and so on `k^(th)` term is increased by `k^(th)` odd integer then sum of 'n' tems is 836 then value of `(n/6) is

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`1.83`
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The terms of an arithmetic sequence add to 715. The first term of the sequence is increased by 1, the second term is increased by 3. the third term is increased by 5, and in general, the rth term is increased by the rth odd positive integer. The terms of the new sequence add to 836. The sum of the first, last, and middle terms of the original sequence is (i) 190 (ii) 96 (iii)200 (iv) 195

The sum of n terms of an AP is 3n^2+5n ,then find its 16th term.

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If sum of n terms of an A.P. is n^(2)+13 , find its 13^(th) term.

If the sum of n terms of an A.P is 2n+3n^(2) , find the r^(th) term

The sum of first n terms of an AP is 4n^(2)+2n Find its n th term.

The sum of the first n terms of an A.P. is 3n^2+6n . Find the n t h term of this A.P.

The sum of first n terms of an A.P.is 5n^(2)+3n If its mth term is 168,(i) Find the value of m (ii) Find the 20th term of this AP

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