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ABCD is a square and E is mid point of A...

ABCD is a square and E is mid point of AD. If area of square is given by `A_(1)`.

A

`("area of " Delta EFD)/("area of " Delta BFC)=(1)/(4)`

B

`("area of " Delta BEF)/("area of " Delta DFC)=1`

C

area of `Delta EFD=(A_(1))/(12)`

D

area of `Delta BEF =(A_(1))/(6)`

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