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Let f(x)=Sigma(i=1)^(n) (x-xi)^2, where ...

Let `f(x)=Sigma_(i=1)^(n) (x-x_i)^2`, where `x_i` are real coefficients , then which of the following is/are incorrect ?

A

f(x) attains its least value at `x=1/n underset(i=1)overset(n)Sigmax_i`

B

f(x) attains its least value of `x=(x_1+2x_2+3x_3+.....+nx_n)/n`

C

f(x) attains its least value of `x=n underset(i=1)overset(n)Sigmax_i`

D

f(x) attains its least value at `x=underset(i=1)overset(n)Sigmax_i`

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B,C,D
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The standard deviation (sigma) of variate x is the square root of the A.M. of the squares of all deviations of x from the A.M. observations. If x_i//f_i , i=1,2,… n is a frequency distribution then sigma=sqrt(1/N Sigma_(i=1)^(n) f_i(x_i-barx)^2), N=Sigma_(i=1)^(n) f_i and variance is the square of standard deviation. Coefficient of dispersion is sigma/x and coefficient of variation is sigma/x xx 100 The standard deviation for the set of numbers 1,4,5,7,8 is 2.45 then coefficient of dispersion is

The standard deviation (sigma) of variate x is the square root of the A.M. of the squares of all deviations of x from the A.M. observations. If x_i//f_i , i=1,2,… n is a frequency distribution then sigma=sqrt(1/N Sigma_(i=1)^(n) f_i(x_i-barx)^2), N=Sigma_(i=1)^(n) f_i and variance is the square of standard deviation. Coefficient of dispersion is sigma/x and coefficient of variation is sigma/x xx 100 For a given distribution of marks mean is 35.16 and its standard deviation is 19.76 then coefficient of variation is

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