An alpha particle of charge ` 3.2 xx 10 ^(-19) C ` and mass ` 6.8 xx 10 ^(-27) Kg ` is initially moving at speed ` 10 ^(7) m/s` when it is at far distance from another fixed point charge ` 112 xx 10 ^(-19) C`. Find the distance of closest approach.

Explanation

To find the distance of closest approach of an alpha particle to a fixed point charge, we will use the principle of conservation of energy. The kinetic energy of the alpha particle will be converted into electric potential energy as it approaches the point charge.

### Step-by-step Solution:

1. **Identify the given values:**
- Charge of the alpha particle, \( q_1 = 3.2 \times 10^{-19} \, C \)
- Charge of the fixed point charge, \( q_2 = 1.12 \times 10^{-19} \, C \)
- Mass of the alpha particle, \( m = 6.8 \times 10^{-27} \, kg \)
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