An electric dipole of dipole moment ` 40 xx 10 ^(-6) C -m` is enclosed by a closed surface. What is the net flux coming out of the surface?

Explanation

To solve the problem of finding the net electric flux coming out of a closed surface that encloses an electric dipole, we can follow these steps:

### Step 1: Understand the Concept of Electric Flux
Electric flux (Φ) through a closed surface is given by Gauss's law, which states:
\[ \Phi = \frac{Q_{net}}{\epsilon_0} \]
where \(Q_{net}\) is the net charge enclosed by the surface and \(\epsilon_0\) is the permittivity of free space.
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