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A rectangular loop of wire of size 4 cm ...

A rectangular loop of wire of size `4 cm // 10cm` carries a steady current of `2A`. A straight long wire carrying `5A` current is kept near the loop `(` as shown in figu `)`. If the loop and the wire are coplanar, find the net force on the loop

A

`3.2 xx 10^(-5) N`

B

`1.6 xx 10^(-3) N`

C

`0.4 xx 10^(-4) N`

D

`4 xx 10^(-5) N`

Text Solution

Verified by Experts

The correct Answer is:
B
As `vecF_(AB) = - vecF_(DC) , vecF_(AB) + vecF_(DC) = 0`
`F_(AD) = k_m ( (2I_1I_2)/(a) ) (AB) `
`= ( (10^(-7) N // A) (2 xx 5A xx 2A )(10cm) )/((1cm) ) = 2 xx 10^(-5) N`
Similarly , `F_(BC) = 0.4 xx 10^(-5) N`
thus , ` F_("net") = F_(AD) - F_(BC) = 1.6 xx 10^(-5) N`
(towards right )
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