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The momenta of a body in two perpendicul...

The momenta of a body in two perpendicular directions at any time 't' are given by `P_(X)=2t^(2)+6 and P_(Y)=(3t^(2))/(2)+3`. The force acting on the body at t=2 sec is

A

5 units

B

2 units

C

10 units

D

15 units

Text Solution

Verified by Experts

The correct Answer is:
C
`F_(x)=(dP_(x))/(dt), F_(y)=(dP_(y))/(dt), F=sqrt(F_(x)^(2)+F_(y)^(2))`
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Knowledge Check

  • The coordinates of a moving particle at any time t are given by, x = 2t^(3) and y = 3t^(3) . Acceleration of the particle is given by

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    B
    `t sqrt(468)`
    C
    `234 t^(2)`
    D
    `t sqrt(234)`

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    A
    18N
    B
    54N
    C
    9N
    D
    15N

  • A body of mass 2kg travels according to the law x(t) = pt + qt^(2) + rt^(3) where , q = 4 ms^(-2) , p = 3 ms^(-1) and r = 5 ms^(-3) . The force acting on the body at t = 2s is

    A
    136 N
    B
    134 N
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