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The momenta of a body in two perpendicul...

The momenta of a body in two perpendicular directions at any time 't' are given by `P_(X)=2t^(2)+6 and P_(Y)=(3t^(2))/(2)+3`. The force acting on the body at t=2 sec is

A

5 units

B

2 units

C

10 units

D

15 units

Text Solution

Verified by Experts

The correct Answer is:
C
`F_(x)=(dP_(x))/(dt), F_(y)=(dP_(y))/(dt), F=sqrt(F_(x)^(2)+F_(y)^(2))`
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Knowledge Check

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