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0.01 mole of iodoform (CHI(3)) reacts w...

0.01 mole of iodoform `(CHI_(3))` reacts with Ag to produce a gas whose volume at NTP is
`2CHI_(3)+6Ag to6Agl(s)+C_(2)H_(2)(g)`

A

224 ml

B

112 ml

C

336 ml

D

448 ml

Text Solution

Verified by Experts

The correct Answer is:
B
`{:(2CHI_(3)+6AgrarrC_(2)H_(2)+6AgI),("2 moles 1mole"),("0.01 moles ?"):}`
`therefore" No. of moles of "C_(2)H_(2)=(0.01)/(2)`.
`therefore" Vol. of "C_(2)H_(2)" at S.T.P"`
`=(0.01)/(2)xx22,400 ml="112 ml"`
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