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In a transistor (beta = 45), the voltage...

In a transistor `(beta = 45)`, the voltage across `5 kOmega` load resistance in collector circuit is 5 V. The base current is

A

0.022 mA

B

0.978 mA

C

1.0 mA

D

2.5 mA

Text Solution

Verified by Experts

The correct Answer is:
A
`beta=I_c/I_b:.I_c/I_b=45`
Now `I_cR_L=5V:.I_c=5/R_L=5/(5xx10^(3))=10^(-3)=1mA`
`:.I_b=I_c/45= 10^(-3)/45=0.022 xx10^(-3)A=0.022mA `
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MODERN PUBLICATION-SOLIDS & SEMICONDUCTOR DEVICES-Revision Test
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