In a common - base circuit of transistor , current amplification factor is 0.95 Calculate the emitter current , if base current is 0.2 mA :

Options

A. 4 mA
B. 0.4 mA
C. 2.1 A
D. 0.21 A

Answer

A

Explanation

Here , `0.95=I_c/I_e" or " I_c=0.95I_e`
`I_e = 0.2 xx10^(-3) + 0.95 I_e " or "0.05 I_e = 0.2 xx10^(-3)`
`:. I_e = (0.2 )/(0.05 ) xx 10^(-3) = 4 xx10^(-3) A`