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The collector supply in a common emitter...

The collector supply in a common emitter amplifier is 8V and the voltage drop across the load of `800 Omega` is 0.4 V. If the current gain for common base be `alpha = 0.96`, then the base current is

A

`20muA`

B

`21muA`

C

`22muA`

D

`24muA`

Text Solution

Verified by Experts

The correct Answer is:
A
`beta = alpha . (1- alpha )=(0.96)/(I-0.96)=24 = I_c/I_b`
Then `I_c = (0.4)/800 and I_b=I_c/24`
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