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For common emitter circuit of a transist...

For common emitter circuit of a transistor , when the base current changes by `80 muA`, the collector current change by 4.8 mA. Then the current amplification factor will be :

A

120

B

30

C

60

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C

`beta = ((DeltaI_c)/(DeltaI_b))=(4.8xx10^(-3))/(80xx10^(-6))=60`
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