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In an n-p-n transistor, the current gain...

In an `n-p-n` transistor, the current gain for common emitter configuration is 80. If the emitter current be 8.1 mA, then base current is

A

`0.1 muA`

B

`0.01 mA`

C

`0.1 mA`

D

`0.01 mA`

Text Solution

Verified by Experts

The correct Answer is:
B
`beta = I_c/I_b = (I_e-I_b)/(I_b), ` then `I_b =I_e/81 =(8.1)/81 = 0.1mA`
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