The transfer ratio `beta` of a transistor is 50. The input resistance of the transistor when used in the common-emitter configuration is `1 kOmega`. The peak value of the collector ac current for an ac input voltage of 0.01 V peak is

Options

A. `0.25 muA`
B. `0.01 muA`
C. `500 muA`
D. `100 muA`

Answer

C

Explanation

Here , `i_b=V_i/R_i=(0.01)/10^3A=10^(-5)A`
Then , `i_c/i_b=beta=50xx10^(-5)A`
`:. i_c=500 muA`