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A transistor is connected in common emit...

A transistor is connected in common emitter configuration . The collector emitter voltage is 8 V and a load resistance of `800 Omega` is connected in the collector circuit . The voltage drop across the load resistance is 0.5 V . If the current gain be 0.96 , the base current is :

A

`5 muA`

B

`8muA`

C

`9.6 muA`

D

None of the above.

Text Solution

Verified by Experts

The correct Answer is:
D
`I_c=(DeltaV_(ec))/R_L=(0.5)/800=5/8mA :.I_b=I_e-I_c=I_c/I_alpha-I_c`
`=26muA`
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