Two triodes A and B have plate amplifications factor of 40 . The plate resistance are `4kOmega and 8 kOmega` respectively. If an amplifier circuit is made using any one of them with a load with a load resistance of `8kOmega` , the ratio of voltage gain obtained from them will be :

Options

A. `4/3`
B. `2/3`
C. `4/9`
D. `5/1`

Answer

A

Explanation

`A_1/A_2=((1+(r_(p_2))/R_L))/((1+(r_(p_1))/R_L))=(1+8/8)/(1+4/8)=(2xx8)/12=4/3`