For a transistor the current amplification factor is 0.8 . If the transistor is now in common emitter configuration , the change in collector current when the base current changes by 6 mA is :

Options

A. 6 mA
B. 4.8 mA
C. 24 mA
D. 8 mA

Answer

C

Explanation

As `alpha = 0.8 and beta = alpha/(1-alpha) =(0.8)/(1-0.8)=4`
`(DeltaI_c)/(DeltaI_b) = 4 " or "DeltaI_c=4xx6 mA = 24 mA`