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In the following common emitter configur...

In the following common emitter configuration an NPN transistor with current gain `beta = 100` is used . The output voltage of the amplifier will be

A

10 V

B

0.1 V

C

1.0 V

D

10 V

Text Solution

Verified by Experts

The correct Answer is:
B
`V_("input")=10^(-3)V, beta=100`
`V_("out") = beta xx "Input"=100 xx10^(-3)=0.1V`
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