A Ge specimen is doped with Al. The concentration of acceptor atoms is `~10^(21)` atoms/ `m^3` . Given that the intrinsic concentration of electron hole Paris is `~10^(19)//m^3` , the concentration of electrons in the specimen is :

Options

A. `10^(17)//m^3`
B. `10^(15)//m^3`
C. `10^(4)//m^3`
D. `10^2//m^3`

Answer

A

Explanation

`n_i^2=n_exxn_n`
`:. n_e =(n_i^2)/(n_h)=(10^(19))^2/10^(21)=10^(17)//m^3`