In a common emitter amplifier output resistance is 2000 ohm and input resistance is 5000 ohm. The input signal is of 10 mV and `beta=50`,
Then output voltage is

Options

A. 1.25 V
B. 2.25 V
C. 2.50 V
D. 3.0V

Answer

A

Explanation

Input voltage `Deltav_i = 10mV = 10^(-2)V`
`R_i=2000Omega`
`Deltai_b=(Deltav_i)/(R_i)=15^2/2000=5xx10^(-6)A`
`beta = (Deltai_c)/(Deltai_b)`
Then `Delta_(ic)=beta Delta_(ib) = 2.5 xx10^(-4)A`
Then output voltage
`DeltaV_0 = DeltaI_c xx R_0 = 1.25 V`