A n-p-n transistor is connected in C - E configuration Collector supply is 8 V . The voltage drop across the load resistor of `800Omega` , connected to collector circuit is 0.8 volt . If `alpha = 25/26`

Then collector emitter voltage `(V_("ce"))` is

Options

A. 5.2 V
B. 6.2 V
C. 7.2 V
D. 8.2 V

Answer

C

Explanation

Current gain , `alpha =25//26`
`:. " "beta = alpha/(1- alpha) =(25//26)/(1-25//26)=25`
Collector supply voltage E = 8 V
Output voltage `V_0 = 0.8 V`
`:. V_("ce")=E-V_0= 8 xx 0.8 = 7.2 V`