In the following common emitter configuration an NPN transistor with current gain `beta = 100` is used . The output voltage of the amplifier will be

Options

A. 10 mV
B. 0.1 V
C. 1.0 V
D. 10 V

Answer

C

Explanation

Voltage gain `=("Output voltage")/("Input voltage")`
`V_("out")=V_("in")xx` Voltage gain
`V_("out")=V_("in") xx` Current gain `xx` Resistance gain
`V_("out")xxbeta =(R_L)/(R_(BE))=10^(-3)xx100xx10/1 =1V`