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For an amplifier in C.E. configuration f...

For an amplifier in C.E. configuration for load `1kOmega (h_(fe)=50) and (h_("cc")=25xx10^(-6))` , the current gain is :

A

`-48.78`

B

`-24.8`

C

`-15.7`

D

`-5.2`

Text Solution

Verified by Experts

The correct Answer is:
A
Semiconductor
`A_i=(h_(fe))/(1+h_(ce)R_L)`
Here , `h_(fe)=50`
`h_(ce)=25xx10^(-6)`
`R_L=10000Omega`
`:. A_i=50/(1+25xx10^(-6)xx10^3)`
`=50/(1+0.25)=50/(1.025)=48.78(-ve)`
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